(6-6i)(2+4i)=0

Solution for (6-6i)(2+4i)=0 equation:

(6-6i)(2+4i)=0

We add all the numbers together, and all the variables

(-6i+6)(4i+2)=0

We multiply parentheses ..

(-24i^2-12i+24i+12)=0

We get rid of parentheses

-24i^2-12i+24i+12=0

We add all the numbers together, and all the variables

-24i^2+12i+12=0

a = -24; b = 12; c = +12;
Δ = b2-4ac
Δ = 122-4·(-24)·12
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-36}{2*-24}=\frac{-48}{-48}
=1
$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+36}{2*-24}=\frac{24}{-48}
=-1/2
$