(6-5i)/(3+2i)=0

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Solution for (6-5i)/(3+2i)=0 equation: 



(6-5i)/(3+2i)=0



Domain of the equation: (3+2i)!=0

We move all terms containing i to the left, all other terms to the right

2i!=-3

i!=-3/2

i!=-1+1/2

i∈R



We add all the numbers together, and all the variables

(-5i+6)/(2i+3)=0

We multiply all the terms by the denominator


(-5i+6)=0

We get rid of parentheses

-5i+6=0

We move all terms containing i to the left, all other terms to the right

-5i=-6

i=-6/-5

i=1+1/5

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