(6-4x)=1-(2x+8)

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Solution for (6-4x)=1-(2x+8) equation: 



(6-4x)=1-(2x+8)

We move all terms to the left:

(6-4x)-(1-(2x+8))=0

We add all the numbers together, and all the variables

(-4x+6)-(1-(2x+8))=0

We get rid of parentheses

-4x-(1-(2x+8))+6=0



We calculate terms in parentheses: -(1-(2x+8)), so:

1-(2x+8)

determiningTheFunctionDomain
-(2x+8)+1

We get rid of parentheses

-2x-8+1

We add all the numbers together, and all the variables

-2x-7

Back to the equation:

-(-2x-7)



We get rid of parentheses

-4x+2x+7+6=0

We add all the numbers together, and all the variables

-2x+13=0

We move all terms containing x to the left, all other terms to the right

-2x=-13

x=-13/-2

x=6+1/2

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