(6-3x)(62x)=36

Solution for (6-3x)(62x)=36 equation:

(6-3x)(62x)=36

We move all terms to the left:

(6-3x)(62x)-(36)=0

We add all the numbers together, and all the variables

(-3x+6)62x-36=0

We multiply parentheses

-186x^2+372x-36=0

a = -186; b = 372; c = -36;
Δ = b2-4ac
Δ = 3722-4·(-186)·(-36)
Δ = 111600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{111600}=\sqrt{3600*31}=\sqrt{3600}*\sqrt{31}=60\sqrt{31}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(372)-60\sqrt{31}}{2*-186}=\frac{-372-60\sqrt{31}}{-372}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(372)+60\sqrt{31}}{2*-186}=\frac{-372+60\sqrt{31}}{-372}
$