(6-2i)/(3+i)

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Solution for (6-2i)/(3+i) equation: 


D( i )

i+3 = 0

i+3 = 0

i+3 = 0

i+3 = 0 // - 3

i = -3

i in (-oo:-3) U (-3:+oo)

(6-(2*i))/(i+3) = 0

(6-2*i)/(i+3) = 0

6-2*i = 0 // - 6

-2*i = -6 // : -2

i = -6/(-2)

i = 3

i = 3

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