(6-2i)(3+i)=

Solution for (6-2i)(3+i)= equation:

Simplifying
(6 + -2i)(3 + i) = 0

Multiply (6 + -2i) * (3 + i)
(6(3 + i) + -2i * (3 + i)) = 0
((3 * 6 + i * 6) + -2i * (3 + i)) = 0
((18 + 6i) + -2i * (3 + i)) = 0
(18 + 6i + (3 * -2i + i * -2i)) = 0
(18 + 6i + (-6i + -2i2)) = 0

Combine like terms: 6i + -6i = 0
(18 + 0 + -2i2) = 0
(18 + -2i2) = 0

Solving
18 + -2i2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-18' to each side of the equation.
18 + -18 + -2i2 = 0 + -18

Combine like terms: 18 + -18 = 0
0 + -2i2 = 0 + -18
-2i2 = 0 + -18

Combine like terms: 0 + -18 = -18
-2i2 = -18

Divide each side by '-2'.
i2 = 9

Simplifying
i2 = 9

Take the square root of each side:
i = {-3, 3}