(6+v)5v+2)=0

Solution for (6+v)5v+2)=0 equation:

(6+v)5v+2)=0

We add all the numbers together, and all the variables

(v+6)5v+2)=0

We add all the numbers together, and all the variables

(v+6)5v=0

We multiply parentheses

5v^2+30v=0

a = 5; b = 30; c = 0;
Δ = b2-4ac
Δ = 302-4·5·0
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-30}{2*5}=\frac{-60}{10}
=-6
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+30}{2*5}=\frac{0}{10}
=0
$