(6+v)(5v-2)=0

Solution for (6+v)(5v-2)=0 equation:

(6+v)(5v-2)=0

We add all the numbers together, and all the variables

(v+6)(5v-2)=0

We multiply parentheses ..

(+5v^2-2v+30v-12)=0

We get rid of parentheses

5v^2-2v+30v-12=0

We add all the numbers together, and all the variables

5v^2+28v-12=0

a = 5; b = 28; c = -12;
Δ = b2-4ac
Δ = 282-4·5·(-12)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-32}{2*5}=\frac{-60}{10}
=-6
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+32}{2*5}=\frac{4}{10}
=2/5
$