(6+8i)(3+5i)=0

Solution for (6+8i)(3+5i)=0 equation:

(6+8i)(3+5i)=0

We add all the numbers together, and all the variables

(8i+6)(5i+3)=0

We multiply parentheses ..

(+40i^2+24i+30i+18)=0

We get rid of parentheses

40i^2+24i+30i+18=0

We add all the numbers together, and all the variables

40i^2+54i+18=0

a = 40; b = 54; c = +18;
Δ = b2-4ac
Δ = 542-4·40·18
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-6}{2*40}=\frac{-60}{80}
=-3/4
$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+6}{2*40}=\frac{-48}{80}
=-3/5
$