(6+4n)+(5+2c)=

Solution for (6+4n)+(5+2c)= equation:

Simplifying
(6 + 4n) + (5 + 2c) = 0

Remove parenthesis around (6 + 4n)
6 + 4n + (5 + 2c) = 0

Remove parenthesis around (5 + 2c)
6 + 4n + 5 + 2c = 0

Reorder the terms:
6 + 5 + 2c + 4n = 0

Combine like terms: 6 + 5 = 11
11 + 2c + 4n = 0

Solving
11 + 2c + 4n = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-11' to each side of the equation.
11 + 2c + -11 + 4n = 0 + -11

Reorder the terms:
11 + -11 + 2c + 4n = 0 + -11

Combine like terms: 11 + -11 = 0
0 + 2c + 4n = 0 + -11
2c + 4n = 0 + -11

Combine like terms: 0 + -11 = -11
2c + 4n = -11

Add '-4n' to each side of the equation.
2c + 4n + -4n = -11 + -4n

Combine like terms: 4n + -4n = 0
2c + 0 = -11 + -4n
2c = -11 + -4n

Divide each side by '2'.
c = -5.5 + -2n

Simplifying
c = -5.5 + -2n