(6+3x)(4+3x)=0

Solution for (6+3x)(4+3x)=0 equation:

(6+3x)(4+3x)=0

We add all the numbers together, and all the variables

(3x+6)(3x+4)=0

We multiply parentheses ..

(+9x^2+12x+18x+24)=0

We get rid of parentheses

9x^2+12x+18x+24=0

We add all the numbers together, and all the variables

9x^2+30x+24=0

a = 9; b = 30; c = +24;
Δ = b2-4ac
Δ = 302-4·9·24
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-6}{2*9}=\frac{-36}{18}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+6}{2*9}=\frac{-24}{18}
=-1+1/3
$