(6+3i)(2-i)=

Solution for (6+3i)(2-i)= equation:

Simplifying
(6 + 3i)(2 + -1i) = 0

Multiply (6 + 3i) * (2 + -1i)
(6(2 + -1i) + 3i * (2 + -1i)) = 0
((2 * 6 + -1i * 6) + 3i * (2 + -1i)) = 0
((12 + -6i) + 3i * (2 + -1i)) = 0
(12 + -6i + (2 * 3i + -1i * 3i)) = 0
(12 + -6i + (6i + -3i2)) = 0

Combine like terms: -6i + 6i = 0
(12 + 0 + -3i2) = 0
(12 + -3i2) = 0

Solving
12 + -3i2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + -3i2 = 0 + -12

Combine like terms: 12 + -12 = 0
0 + -3i2 = 0 + -12
-3i2 = 0 + -12

Combine like terms: 0 + -12 = -12
-3i2 = -12

Divide each side by '-3'.
i2 = 4

Simplifying
i2 = 4

Take the square root of each side:
i = {-2, 2}