(6+2m)=4(3m+12)

Solution for (6+2m)=4(3m+12) equation:

(6+2m)=4(3m+12)

We move all terms to the left:

(6+2m)-(4(3m+12))=0

We add all the numbers together, and all the variables

(2m+6)-(4(3m+12))=0

We get rid of parentheses

2m-(4(3m+12))+6=0


We calculate terms in parentheses: -(4(3m+12)), so:

4(3m+12)

We multiply parentheses

12m+48

Back to the equation:

-(12m+48)


We get rid of parentheses

2m-12m-48+6=0

We add all the numbers together, and all the variables

-10m-42=0

We move all terms containing m to the left, all other terms to the right

-10m=42

m=42/-10

m=-4+1/5