(6)/(y-5)=(18)/(y+1)

Solution for (6)/(y-5)=(18)/(y+1) equation:

(6)/(y-5)=(18)/(y+1)

We move all terms to the left:

(6)/(y-5)-((18)/(y+1))=0


Domain of the equation: (y-5)!=0

We move all terms containing y to the left, all other terms to the right

y!=5

y∈R



Domain of the equation: (y+1))!=0

y∈R


We calculate fractions


6y/((y-5)*(y+1)))+(-(18*(y-5))/((y-5)*(y+1)))=0


We calculate terms in parentheses: -(18*(y-5))/((y-5)*(y+1))), so:

18*(y-5))/((y-5)*(y+1))

We multiply all the terms by the denominator


18*(y-5))

We multiply parentheses

18y+

We add all the numbers together, and all the variables

18y

Back to the equation:

-(18y)


We add all the numbers together, and all the variables

-18y+6y/((y-5)*(y+1)))+(=0

We multiply all the terms by the denominator


-18y*((y-5)*(y+1)))+(+6y=0

We add all the numbers together, and all the variables

6y-18y*((y-5)*(y+1)))+(=0