(6)/(45)=(2z+10)/(15)

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Solution for (6)/(45)=(2z+10)/(15) equation:



(6)/(45)=(2z+10)/(15)
We move all terms to the left:
(6)/(45)-((2z+10)/(15))=0
We calculate fractions
(-((2z+10)*45)/()+()/()=0
We calculate terms in parentheses: +(-((2z+10)*45)/()+()/(), so:
-((2z+10)*45)/()+()/(
We add all the numbers together, and all the variables
-((2z+10)*45)/()+1
We multiply all the terms by the denominator
-((2z+10)*45)+1*()
We calculate terms in parentheses: -((2z+10)*45), so:
(2z+10)*45
We multiply parentheses
90z+450
Back to the equation:
-(90z+450)
We add all the numbers together, and all the variables
-(90z+450)
We get rid of parentheses
-90z-450
Back to the equation:
+(-90z-450)
We get rid of parentheses
-90z-450=0
We move all terms containing z to the left, all other terms to the right
-90z=450
z=450/-90
z=-5

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