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D( x )
(25/15)*x = 0
(25/15)*x = 0
(25/15)*x = 0
5/3*x = 0 // : 5/3
x = 0
x in (-oo:0) U (0:+oo)
(x*((5*y)/3))/((25/15)*x) = 0
y = 0
x należy do R
x in (-oo:0) U (0:+oo)
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