(5y/2y-1)-3=(12/2y-1)

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Solution for (5y/2y-1)-3=(12/2y-1) equation: 


y in (-oo:+oo)

((5*y)/2)*y-3-1 = (12/2)*y-1 // - (12/2)*y-1

((5*y)/2)*y-((12/2)*y)-3-1+1 = 0

((5*y)/2)*y-6*y-3-1+1 = 0

5/2*y^2-6*y-3 = 0

DELTA = (-6)^2-(-3*5/2*4)

DELTA = 66

DELTA > 0

y = (66^(1/2)+6)/(2*5/2) or y = (6-66^(1/2))/(2*5/2)

y = (66^(1/2)+6)/5 or y = (6-66^(1/2))/5

y in { (6-66^(1/2))/5, (66^(1/2)+6)/5 }

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