(5y-7)=(y-1)

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Solution for (5y-7)=(y-1) equation: 



(5y-7)=(y-1)

We move all terms to the left:

(5y-7)-((y-1))=0

We get rid of parentheses

5y-((y-1))-7=0



We calculate terms in parentheses: -((y-1)), so:

(y-1)

We get rid of parentheses

y-1

Back to the equation:

-(y-1)



We get rid of parentheses

5y-y+1-7=0

We add all the numbers together, and all the variables

4y-6=0

We move all terms containing y to the left, all other terms to the right

4y=6

y=6/4

y=1+1/2

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