(5y-4)+(7y+3)=(20y-9)

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Solution for (5y-4)+(7y+3)=(20y-9) equation:


Simplifying
(5y + -4) + (7y + 3) = (20y + -9)

Reorder the terms:
(-4 + 5y) + (7y + 3) = (20y + -9)

Remove parenthesis around (-4 + 5y)
-4 + 5y + (7y + 3) = (20y + -9)

Reorder the terms:
-4 + 5y + (3 + 7y) = (20y + -9)

Remove parenthesis around (3 + 7y)
-4 + 5y + 3 + 7y = (20y + -9)

Reorder the terms:
-4 + 3 + 5y + 7y = (20y + -9)

Combine like terms: -4 + 3 = -1
-1 + 5y + 7y = (20y + -9)

Combine like terms: 5y + 7y = 12y
-1 + 12y = (20y + -9)

Reorder the terms:
-1 + 12y = (-9 + 20y)

Remove parenthesis around (-9 + 20y)
-1 + 12y = -9 + 20y

Solving
-1 + 12y = -9 + 20y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-20y' to each side of the equation.
-1 + 12y + -20y = -9 + 20y + -20y

Combine like terms: 12y + -20y = -8y
-1 + -8y = -9 + 20y + -20y

Combine like terms: 20y + -20y = 0
-1 + -8y = -9 + 0
-1 + -8y = -9

Add '1' to each side of the equation.
-1 + 1 + -8y = -9 + 1

Combine like terms: -1 + 1 = 0
0 + -8y = -9 + 1
-8y = -9 + 1

Combine like terms: -9 + 1 = -8
-8y = -8

Divide each side by '-8'.
y = 1

Simplifying
y = 1

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