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(5y-2)(12y-7)=0
We multiply parentheses ..
(+60y^2-35y-24y+14)=0
We get rid of parentheses
60y^2-35y-24y+14=0
We add all the numbers together, and all the variables
60y^2-59y+14=0
a = 60; b = -59; c = +14;
Δ = b2-4ac
Δ = -592-4·60·14
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-59)-11}{2*60}=\frac{48}{120} =2/5 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-59)+11}{2*60}=\frac{70}{120} =7/12 $
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