(5y+4)(1,1y-3,3)=0

Solution for (5y+4)(1,1y-3,3)=0 equation:

(5y+4)(1.1y-3.3)=0

We multiply parentheses ..

(+5y^2-16.5y+4y-13.2)=0

We get rid of parentheses

5y^2-16.5y+4y-13.2=0

We add all the numbers together, and all the variables

5y^2-12.5y-13.2=0

a = 5; b = -12.5; c = -13.2;
Δ = b2-4ac
Δ = -12.52-4·5·(-13.2)
Δ = 420.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12.5)-\sqrt{420.25}}{2*5}=\frac{12.5-\sqrt{420.25}}{10}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12.5)+\sqrt{420.25}}{2*5}=\frac{12.5+\sqrt{420.25}}{10}
$