(5y+21)=(7y-1)

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Solution for (5y+21)=(7y-1) equation: 



(5y+21)=(7y-1)

We move all terms to the left:

(5y+21)-((7y-1))=0

We get rid of parentheses

5y-((7y-1))+21=0



We calculate terms in parentheses: -((7y-1)), so:

(7y-1)

We get rid of parentheses

7y-1

Back to the equation:

-(7y-1)



We get rid of parentheses

5y-7y+1+21=0

We add all the numbers together, and all the variables

-2y+22=0

We move all terms containing y to the left, all other terms to the right

-2y=-22

y=-22/-2

y=+11

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