(5y+2)(5y-2)=0

Solution for (5y+2)(5y-2)=0 equation:

Simplifying
(5y + 2)(5y + -2) = 0

Reorder the terms:
(2 + 5y)(5y + -2) = 0

Reorder the terms:
(2 + 5y)(-2 + 5y) = 0

Multiply (2 + 5y) * (-2 + 5y)
(2(-2 + 5y) + 5y * (-2 + 5y)) = 0
((-2 * 2 + 5y * 2) + 5y * (-2 + 5y)) = 0
((-4 + 10y) + 5y * (-2 + 5y)) = 0
(-4 + 10y + (-2 * 5y + 5y * 5y)) = 0
(-4 + 10y + (-10y + 25y2)) = 0

Combine like terms: 10y + -10y = 0
(-4 + 0 + 25y2) = 0
(-4 + 25y2) = 0

Solving
-4 + 25y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 25y2 = 0 + 4

Combine like terms: -4 + 4 = 0
0 + 25y2 = 0 + 4
25y2 = 0 + 4

Combine like terms: 0 + 4 = 4
25y2 = 4

Divide each side by '25'.
y2 = 0.16

Simplifying
y2 = 0.16

Take the square root of each side:
y = {-0.4, 0.4}