(5x2+7x+8)+(3x2+4x+2)=

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Solution for (5x2+7x+8)+(3x2+4x+2)= equation: 



(5x^2+7x+8)+(3x^2+4x+2)=

We move all terms to the left:

(5x^2+7x+8)+(3x^2+4x+2)-()=0

We add all the numbers together, and all the variables

(5x^2+7x+8)+(3x^2+4x+2)=0

We get rid of parentheses

5x^2+3x^2+7x+4x+8+2=0

We add all the numbers together, and all the variables

8x^2+11x+10=0

a = 8; b = 11; c = +10;
Δ = b2-4ac
Δ = 112-4·8·10
Δ = -199
Delta is less than zero, so there is no solution for the equation

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