(5x/2)+(2/3)=(-7/12)

Solution for (5x/2)+(2/3)=(-7/12) equation:

(5x/2)+(2/3)=(-7/12)

We move all terms to the left:

(5x/2)+(2/3)-((-7/12))=0

We add all the numbers together, and all the variables

(+5x/2)+(+2/3)-((-7/12))=0

We get rid of parentheses

5x/2+2/3-((-7/12))=0

We calculate fractions


180x^2/()+()/()+()/()=0

We add all the numbers together, and all the variables

180x^2/()+2=0

We multiply all the terms by the denominator


180x^2+2*()=0

We add all the numbers together, and all the variables

180x^2=0

a = 180; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·180·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{360}=0$