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(5x-9)(5x-8)=0
We multiply parentheses ..
(+25x^2-40x-45x+72)=0
We get rid of parentheses
25x^2-40x-45x+72=0
We add all the numbers together, and all the variables
25x^2-85x+72=0
a = 25; b = -85; c = +72;
Δ = b2-4ac
Δ = -852-4·25·72
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-85)-5}{2*25}=\frac{80}{50} =1+3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-85)+5}{2*25}=\frac{90}{50} =1+4/5 $
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