(5x-8)+(3x+20)=x

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Solution for (5x-8)+(3x+20)=x equation: 



(5x-8)+(3x+20)=x

We move all terms to the left:

(5x-8)+(3x+20)-(x)=0

We add all the numbers together, and all the variables

-1x+(5x-8)+(3x+20)=0

We get rid of parentheses

-1x+5x+3x-8+20=0

We add all the numbers together, and all the variables

7x+12=0

We move all terms containing x to the left, all other terms to the right

7x=-12

x=-12/7

x=-1+5/7

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