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(5x-7)x=163
We move all terms to the left:
(5x-7)x-(163)=0
We multiply parentheses
5x^2-7x-163=0
a = 5; b = -7; c = -163;
Δ = b2-4ac
Δ = -72-4·5·(-163)
Δ = 3309
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{3309}}{2*5}=\frac{7-\sqrt{3309}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{3309}}{2*5}=\frac{7+\sqrt{3309}}{10} $
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