(5x-6)(2x+3)(2x+3)(3x-2)=2x(8x+1)

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Solution for (5x-6)(2x+3)(2x+3)(3x-2)=2x(8x+1) equation: 



(5x-6)(2x+3)(2x+3)(3x-2)=2x(8x+1)

We move all terms to the left:

(5x-6)(2x+3)(2x+3)(3x-2)-(2x(8x+1))=0

We multiply parentheses ..

(+10x^2+15x-12x-18)(2x+3)(3x-2)-(2x(8x+1))=0



We calculate terms in parentheses: -(2x(8x+1)), so:

2x(8x+1)

We multiply parentheses

16x^2+2x

Back to the equation:

-(16x^2+2x)



We get rid of parentheses

(+10x^2+15x-12x-18)(2x+3)(3x-2)-16x^2-2x=0

We multiply parentheses ..

(+10x^2+15x-12x-18)(+6x^2-4x+9x-6)-16x^2-2x=0

We add all the numbers together, and all the variables

-16x^2+(+10x^2+15x-12x-18)(+6x^2-4x+9x-6)-2x=0

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