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(5x-6)(-2x+6)=0
We multiply parentheses ..
(-10x^2+30x+12x-36)=0
We get rid of parentheses
-10x^2+30x+12x-36=0
We add all the numbers together, and all the variables
-10x^2+42x-36=0
a = -10; b = 42; c = -36;
Δ = b2-4ac
Δ = 422-4·(-10)·(-36)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-18}{2*-10}=\frac{-60}{-20} =+3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+18}{2*-10}=\frac{-24}{-20} =1+1/5 $
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