(5x-5)/4=(4x-4)/3

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Solution for (5x-5)/4=(4x-4)/3 equation: 



(5x-5)/4=(4x-4)/3

We move all terms to the left:

(5x-5)/4-((4x-4)/3)=0

We calculate fractions


5x/()+(-((4x-4)*4)/()=0



We calculate terms in parentheses: +(-((4x-4)*4)/(), so:

-((4x-4)*4)/(

We multiply all the terms by the denominator


-((4x-4)*4)



We calculate terms in parentheses: -((4x-4)*4), so:

(4x-4)*4

We multiply parentheses

16x-16

Back to the equation:

-(16x-16)



We get rid of parentheses

-16x+16

Back to the equation:

+(-16x+16)



We get rid of parentheses

5x/()-16x+16=0

We multiply all the terms by the denominator


5x-16x*()+16*()=0

We add all the numbers together, and all the variables

5x-16x*()=0

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