(5x-5)+(7x-19)+x=72

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Solution for (5x-5)+(7x-19)+x=72 equation: 



(5x-5)+(7x-19)+x=72

We move all terms to the left:

(5x-5)+(7x-19)+x-(72)=0

We add all the numbers together, and all the variables

x+(5x-5)+(7x-19)-72=0

We get rid of parentheses

x+5x+7x-5-19-72=0

We add all the numbers together, and all the variables

13x-96=0

We move all terms containing x to the left, all other terms to the right

13x=96

x=96/13

x=7+5/13

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