(5x-5)*(2x+2)=0

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Solution for (5x-5)*(2x+2)=0 equation:


Simplifying
(5x + -5)(2x + 2) = 0

Reorder the terms:
(-5 + 5x)(2x + 2) = 0

Reorder the terms:
(-5 + 5x)(2 + 2x) = 0

Multiply (-5 + 5x) * (2 + 2x)
(-5(2 + 2x) + 5x * (2 + 2x)) = 0
((2 * -5 + 2x * -5) + 5x * (2 + 2x)) = 0
((-10 + -10x) + 5x * (2 + 2x)) = 0
(-10 + -10x + (2 * 5x + 2x * 5x)) = 0
(-10 + -10x + (10x + 10x2)) = 0

Combine like terms: -10x + 10x = 0
(-10 + 0 + 10x2) = 0
(-10 + 10x2) = 0

Solving
-10 + 10x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 10 + 10x2 = 0 + 10

Combine like terms: -10 + 10 = 0
0 + 10x2 = 0 + 10
10x2 = 0 + 10

Combine like terms: 0 + 10 = 10
10x2 = 10

Divide each side by '10'.
x2 = 1

Simplifying
x2 = 1

Take the square root of each side:
x = {-1, 1}

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