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(5x-5)(x-8)=-28+34
We move all terms to the left:
(5x-5)(x-8)-(-28+34)=0
We add all the numbers together, and all the variables
(5x-5)(x-8)-6=0
We multiply parentheses ..
(+5x^2-40x-5x+40)-6=0
We get rid of parentheses
5x^2-40x-5x+40-6=0
We add all the numbers together, and all the variables
5x^2-45x+34=0
a = 5; b = -45; c = +34;
Δ = b2-4ac
Δ = -452-4·5·34
Δ = 1345
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-\sqrt{1345}}{2*5}=\frac{45-\sqrt{1345}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+\sqrt{1345}}{2*5}=\frac{45+\sqrt{1345}}{10} $
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