(5x-4)/6=(4x+1)-(3x+10)/2

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Solution for (5x-4)/6=(4x+1)-(3x+10)/2 equation: 



(5x-4)/6=(4x+1)-(3x+10)/2

We move all terms to the left:

(5x-4)/6-((4x+1)-(3x+10)/2)=0

We calculate fractions


5x/()+(-((4x+1)-(3x+10)*6)/()=0



We calculate terms in parentheses: +(-((4x+1)-(3x+10)*6)/(), so:

-((4x+1)-(3x+10)*6)/(

We multiply all the terms by the denominator


-((4x+1)-(3x+10)*6)



We calculate terms in parentheses: -((4x+1)-(3x+10)*6), so:

(4x+1)-(3x+10)*6

We multiply parentheses

(4x+1)-18x-60

We get rid of parentheses

4x-18x+1-60

We add all the numbers together, and all the variables

-14x-59

Back to the equation:

-(-14x-59)



We get rid of parentheses

14x+59

Back to the equation:

+(14x+59)



We get rid of parentheses

5x/()+14x+59=0

We multiply all the terms by the denominator


5x+14x*()+59*()=0

We add all the numbers together, and all the variables

5x+14x*()=0

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