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(5x-4)(x-6)(3)=600
We move all terms to the left:
(5x-4)(x-6)(3)-(600)=0
We multiply parentheses ..
(+5x^2-30x-4x+24)3-600=0
We multiply parentheses
15x^2-90x-12x+72-600=0
We add all the numbers together, and all the variables
15x^2-102x-528=0
a = 15; b = -102; c = -528;
Δ = b2-4ac
Δ = -1022-4·15·(-528)
Δ = 42084
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{42084}=\sqrt{36*1169}=\sqrt{36}*\sqrt{1169}=6\sqrt{1169}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-102)-6\sqrt{1169}}{2*15}=\frac{102-6\sqrt{1169}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-102)+6\sqrt{1169}}{2*15}=\frac{102+6\sqrt{1169}}{30} $
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