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(5x-4)(5x+6)=0
We multiply parentheses ..
(+25x^2+30x-20x-24)=0
We get rid of parentheses
25x^2+30x-20x-24=0
We add all the numbers together, and all the variables
25x^2+10x-24=0
a = 25; b = 10; c = -24;
Δ = b2-4ac
Δ = 102-4·25·(-24)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-50}{2*25}=\frac{-60}{50} =-1+1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+50}{2*25}=\frac{40}{50} =4/5 $
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