(5x-3)/4=(6x+1)/8

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Solution for (5x-3)/4=(6x+1)/8 equation: 



(5x-3)/4=(6x+1)/8

We move all terms to the left:

(5x-3)/4-((6x+1)/8)=0

We calculate fractions


5x/()+(-((6x+1)*4)/()=0



We calculate terms in parentheses: +(-((6x+1)*4)/(), so:

-((6x+1)*4)/(

We multiply all the terms by the denominator


-((6x+1)*4)



We calculate terms in parentheses: -((6x+1)*4), so:

(6x+1)*4

We multiply parentheses

24x+4

Back to the equation:

-(24x+4)



We get rid of parentheses

-24x-4

Back to the equation:

+(-24x-4)



We get rid of parentheses

5x/()-24x-4=0

We multiply all the terms by the denominator


5x-24x*()-4*()=0

We add all the numbers together, and all the variables

5x-24x*()=0

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