(5x-3)+(5x-3)+(4x+2)+(4x+2)=160

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Solution for (5x-3)+(5x-3)+(4x+2)+(4x+2)=160 equation: 



(5x-3)+(5x-3)+(4x+2)+(4x+2)=160

We move all terms to the left:

(5x-3)+(5x-3)+(4x+2)+(4x+2)-(160)=0

We get rid of parentheses

5x+5x+4x+4x-3-3+2+2-160=0

We add all the numbers together, and all the variables

18x-162=0

We move all terms containing x to the left, all other terms to the right

18x=162

x=162/18

x=9

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