(5x-3)+(10x-20)+(4x-2)=180

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Solution for (5x-3)+(10x-20)+(4x-2)=180 equation: 



(5x-3)+(10x-20)+(4x-2)=180

We move all terms to the left:

(5x-3)+(10x-20)+(4x-2)-(180)=0

We get rid of parentheses

5x+10x+4x-3-20-2-180=0

We add all the numbers together, and all the variables

19x-205=0

We move all terms containing x to the left, all other terms to the right

19x=205

x=205/19

x=10+15/19

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