(5x-3)(x+2)=(x-)2-20

Solution for (5x-3)(x+2)=(x-)2-20 equation:

(5x-3)(x+2)=(x-)2-20

We move all terms to the left:

(5x-3)(x+2)-((x-)2-20)=0

We add all the numbers together, and all the variables

(5x-3)(x+2)-((+x)2-20)=0

We multiply parentheses ..

(+5x^2+10x-3x-6)-((+x)2-20)=0


We calculate terms in parentheses: -((+x)2-20), so:

(+x)2-20

We multiply parentheses

2x-20

Back to the equation:

-(2x-20)


We get rid of parentheses

5x^2+10x-3x-2x-6+20=0

We add all the numbers together, and all the variables

5x^2+5x+14=0

a = 5; b = 5; c = +14;
Δ = b2-4ac
Δ = 52-4·5·14
Δ = -255
Delta is less than zero, so there is no solution for the equation