(5x-3)(9+x)=180

Solution for (5x-3)(9+x)=180 equation:

(5x-3)(9+x)=180

We move all terms to the left:

(5x-3)(9+x)-(180)=0

We add all the numbers together, and all the variables

(5x-3)(x+9)-180=0

We multiply parentheses ..

(+5x^2+45x-3x-27)-180=0

We get rid of parentheses

5x^2+45x-3x-27-180=0

We add all the numbers together, and all the variables

5x^2+42x-207=0

a = 5; b = 42; c = -207;
Δ = b2-4ac
Δ = 422-4·5·(-207)
Δ = 5904
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5904}=\sqrt{144*41}=\sqrt{144}*\sqrt{41}=12\sqrt{41}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-12\sqrt{41}}{2*5}=\frac{-42-12\sqrt{41}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+12\sqrt{41}}{2*5}=\frac{-42+12\sqrt{41}}{10}
$