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(5x-3)(2x+8)=180
We move all terms to the left:
(5x-3)(2x+8)-(180)=0
We multiply parentheses ..
(+10x^2+40x-6x-24)-180=0
We get rid of parentheses
10x^2+40x-6x-24-180=0
We add all the numbers together, and all the variables
10x^2+34x-204=0
a = 10; b = 34; c = -204;
Δ = b2-4ac
Δ = 342-4·10·(-204)
Δ = 9316
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9316}=\sqrt{4*2329}=\sqrt{4}*\sqrt{2329}=2\sqrt{2329}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-2\sqrt{2329}}{2*10}=\frac{-34-2\sqrt{2329}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+2\sqrt{2329}}{2*10}=\frac{-34+2\sqrt{2329}}{20} $
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