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(5x-3)(2x+7)=0
We multiply parentheses ..
(+10x^2+35x-6x-21)=0
We get rid of parentheses
10x^2+35x-6x-21=0
We add all the numbers together, and all the variables
10x^2+29x-21=0
a = 10; b = 29; c = -21;
Δ = b2-4ac
Δ = 292-4·10·(-21)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-41}{2*10}=\frac{-70}{20} =-3+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+41}{2*10}=\frac{12}{20} =3/5 $
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