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(5x-28)(3x+4)=90
We move all terms to the left:
(5x-28)(3x+4)-(90)=0
We multiply parentheses ..
(+15x^2+20x-84x-112)-90=0
We get rid of parentheses
15x^2+20x-84x-112-90=0
We add all the numbers together, and all the variables
15x^2-64x-202=0
a = 15; b = -64; c = -202;
Δ = b2-4ac
Δ = -642-4·15·(-202)
Δ = 16216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{16216}=\sqrt{4*4054}=\sqrt{4}*\sqrt{4054}=2\sqrt{4054}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-2\sqrt{4054}}{2*15}=\frac{64-2\sqrt{4054}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+2\sqrt{4054}}{2*15}=\frac{64+2\sqrt{4054}}{30} $
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