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(5x-27)(4x+23)=0
We multiply parentheses ..
(+20x^2+115x-108x-621)=0
We get rid of parentheses
20x^2+115x-108x-621=0
We add all the numbers together, and all the variables
20x^2+7x-621=0
a = 20; b = 7; c = -621;
Δ = b2-4ac
Δ = 72-4·20·(-621)
Δ = 49729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49729}=223$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-223}{2*20}=\frac{-230}{40} =-5+3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+223}{2*20}=\frac{216}{40} =5+2/5 $
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