(5x-27)(2x+42=)

Solution for (5x-27)(2x+42=) equation:

(5x-27)(2x+42=)

We move all terms to the left:

(5x-27)(2x+42-())=0


We calculate terms in parentheses: +(5x-27)(2x+42-()), so:

5x-27)(2x+42-()

We add all the numbers together, and all the variables

5x-27)(2x

Back to the equation:

+(5x-27)(2x)


We multiply parentheses

10x^2-54x=0

a = 10; b = -54; c = 0;
Δ = b2-4ac
Δ = -542-4·10·0
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2916}=54$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-54}{2*10}=\frac{0}{20}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+54}{2*10}=\frac{108}{20}
=5+2/5
$