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(5x-20)=(x+32)
We move all terms to the left:
(5x-20)-((x+32))=0
We get rid of parentheses
5x-((x+32))-20=0
We calculate terms in parentheses: -((x+32)), so:We get rid of parentheses
(x+32)
We get rid of parentheses
x+32
Back to the equation:
-(x+32)
5x-x-32-20=0
We add all the numbers together, and all the variables
4x-52=0
We move all terms containing x to the left, all other terms to the right
4x=52
x=52/4
x=13
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