(5x-2)/3=(6x+4)/8

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Solution for (5x-2)/3=(6x+4)/8 equation: 



(5x-2)/3=(6x+4)/8

We move all terms to the left:

(5x-2)/3-((6x+4)/8)=0

We calculate fractions


5x/()+(-((6x+4)*3)/()=0



We calculate terms in parentheses: +(-((6x+4)*3)/(), so:

-((6x+4)*3)/(

We multiply all the terms by the denominator


-((6x+4)*3)



We calculate terms in parentheses: -((6x+4)*3), so:

(6x+4)*3

We multiply parentheses

18x+12

Back to the equation:

-(18x+12)



We get rid of parentheses

-18x-12

Back to the equation:

+(-18x-12)



We get rid of parentheses

5x/()-18x-12=0

We multiply all the terms by the denominator


5x-18x*()-12*()=0

We add all the numbers together, and all the variables

5x-18x*()=0

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