(5x-2)-(3-2x)=(x-4)-(x+1)

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Solution for (5x-2)-(3-2x)=(x-4)-(x+1) equation: 



(5x-2)-(3-2x)=(x-4)-(x+1)

We move all terms to the left:

(5x-2)-(3-2x)-((x-4)-(x+1))=0

We add all the numbers together, and all the variables

(5x-2)-(-2x+3)-((x-4)-(x+1))=0

We get rid of parentheses

5x+2x-((x-4)-(x+1))-2-3=0



We calculate terms in parentheses: -((x-4)-(x+1)), so:

(x-4)-(x+1)

We get rid of parentheses

x-x-4-1

We add all the numbers together, and all the variables

-5

Back to the equation:

-(-5)



We add all the numbers together, and all the variables

7x=0

x=0/7

x=0

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